Increase and Decrease in Ratio

If the number of teachers in a college is increased from 50 to 60, then the ratio of new staff and old staff is:

\begin{array}{*{20}{c}} {{\text{No}}{\text{. of new staff}}}&{\text{:}}&{{\text{No}}{\text{. of old staff}}} \\ {{\text{60}}}&{\text{:}}&{{\text{50}}} \\ {\text{6}}&{\text{:}}&{\text{5}} \end{array}

\frac{{{\text{no}}{\text{. of new staff}}}}{{{\text{no}}{\text{. of old staff}}}} = \frac{6}{5}

We say that the number of teachers has been increased by the ratio 6 : 5. In other words, the number of new staff is \frac{6}{5} times the number of old staff.

Hence \boxed{{\text{no}}{\text{. of new staff = }}\frac{{\text{6}}}{{\text{5}}}{\text{ (no}}{\text{. of old staff)}}}


To increase a no. “x”  we multiply x by an improper fraction.


\boxed{{\text{no}}{\text{. of new staff = }}\frac{{\text{6}}}{{\text{5}}}{\text{ (no}}{\text{. of old staff)}}}

Similarly to decrease a no.  “x”  we multiply x by an proper fraction.


\boxed{{\text{no}}{\text{. of old staff = }}\frac{{\text{6}}}{{\text{5}}}{\text{ (no}}{\text{. of new staff)}}}

e.g. (1) Increase Rs. 20 by the ratio 6 : 5
New value = {\text{20 x }}\frac{{\text{6}}}{{\text{5}}} = 24

e.g. (2) Decrease 56 by the ratio 7 : 8
New value =  {\text{56 x }}\frac{{\text{7}}}{{\text{8}}} = 49