In this tutorial we shall find the integral of function, and it is another important integration. To evaluate this integral first we use the method of substitution and then we use integration by parts.
The integral of squared is of the form
But implies that , by differentiation , so the given integral (i) takes the form
Considering and are the first and second functions and using integration by parts, we have
Using the formula for integration by parts, we have
Using the formula above, equation (ii) becomes
Now again using integration by parts, we have
From the above substitution it can be written in the form