# Equation of a Line through the Intersection of Two other Lines

Consider the two straight lines

For any nonzero constant $k$, the equation of the form

being linear in $x$ and $y$, is an equation of straight line.
If $\left( {{x_1},{y_1}} \right)$ is the point of intersection of line (i) and (ii), then it must satisfy both equations (i) and (ii), i.e.

Next we check whether the point $\left( {{x_1},{y_1}} \right)$ lies on (iii) or not. For this we replace $x$ by ${x_1}$ and $y$ by ${y_1}$ in equation (iii), we have

Using equation (iv) and (v) in equation (vi), we get the following result

This shows that (vi) is true for all $k$ and for $x = {x_1},\,y = {y_1}$. Thus, the point $\left( {{x_1},{y_1}} \right)$ lies on (vi) for all $k$. In fact (vi) represents the equation of line through the point of intersection of the lines (i) and (ii). Since $k$ is any real number, so equation (vi) shows that there will be an infinite number of lines through the point of intersection of the lines (i) and (ii).
In order to find the particular line, we must have the particular value of $k$ and this particular value of $k$can be found out with the help of some given condition.

Example: Find the equation of line through the point $\left( {1,3} \right)$ and the point of intersection of lines $2x - 3y + 4 = 0$ and $4x + y - 1 = 0$.
The equation of straight line through the point of intersection of lines $2x - 3y + 4 = 0$ and $4x + y - 1 = 0$ is given as

Since the required above line passes through the point $\left( {1,3} \right)$, so this point must satisfy the equation, i.e.

Putting this value of $k$ in the required equation of straight line, we have

This is the required equation of straight line.