In this tutorial we shall find integral of function, it is also an important integration, to evaluate this integral first use method of substitution then use integration by parts.
The integral of squared is of the form
Put implies that , by differentiation , so the given integral (i) takes the form
Considering and as first and second functions and integration by parts, we have.
Using formula for integration by parts, we have
Equation (ii) becomes using above formula, we have
Now again using integration by parts, we have
From the above substitution it can be written in the form, we get