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» Home » Basic Statistics »

Efficiency of an Estimator

Among a number of estimators of the same class, the estimator having the least variance is called an efficient estimator. Thus, if we have two estimators a1 and a2 with variances var(a1) and  var(a2) respectively, also if var(a1)<var(a2) then a1 will be an efficient estimator. The ratio of the variances of two estimators denoted by e(a1, a2) is known as the efficiency of  a1 and a2 is defined as follows

                                               e(a1, a2)=var(a1)/var(a2)
            If the value of this ratio is more than 1, then a1 will be more efficient, if it is equal to 1, both a1 and a2 are equally efficient and if it is less than 1, then a1 will be less efficient. Let us consider the following worked example.

Example:
            The variances of the sample mean and median are respectively.
                                                 and
            Find the efficiency of

  1. median against mean
  2. mean against median

Solution:

  1. Using the formula  e(a1, a2)    =var(a1)/var(a2), we have

                       e (median, mean) e=var(x)/var(med)
                                                    
                Therefore, the efficiency of median against the mean is only 0.63. It means that a sample mean obtained from a sample of size 63 will be equally efficient to a sample median obtained from a sample of size 100.


  2. Also, using the formula  , we have

                   e (mean, median)
                                              
            Therefore, the efficiency of mean against median is 1.57 or in other words mean is about 57% more efficient than the median.

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